(Facts quickly googled)
Area of Los Angeles: 1.29 * 10⁹ m²
Height of air column over city: say 1000m
Volume of air = 1.29 * 10¹² m³
Mass of air (density 1.29 g/l) = 1.66 * 10¹² kg
Energy of air (700 J/kg for each C) = 2.32 * 10¹⁵ J
Equivalent number of barrels of oil (6.1 * 10⁹ J) = 380327 ~= 0.4 * 10⁶
Daily consumption in all of california: 1.8*10⁶ barrels
If the calculations are right, you would have to burn around 20% of California's daily consumption inside the city to raise the air temperature by 2C.
(Facts quickly googled)
Area of Los Angeles: 1.29 * 10⁹ m²
Height of air column over city: say 1000m
Volume of air = 1.29 * 10¹² m³
Mass of air (density 1.29 g/l) = 1.66 * 10¹² kg
Energy of air (700 J/kg for each C) = 2.32 * 10¹⁵ J
Equivalent number of barrels of oil (6.1 * 10⁹ J) = 380327 ~= 0.4 * 10⁶
Daily consumption in all of california: 1.8*10⁶ barrels
If the calculations are right, you would have to burn around 20% of California's daily consumption inside the city to raise the air temperature by 2C.